请大神们帮忙解释一下红色字体显示的结果是怎么出来的啊，谢谢。

jennyjin

procedure( trMakeComplex( @key ( real 0 ) ( imaginary 0 ) )
let( ( result )
result = ncons(nil)
result->real = real
result->imaginary = imaginary
result
) ; let
) ;procedure
complex1 = trMakeComplex( ?real 2 ?imaginary 3 )
=> (nil imaginary 3 real 2)
complex2 = trMakeComplex( ?real 4 ?imaginary 5 )
=> (nil imaginary 5 real 4)
i = trMakeComplex( ?imaginary 1 )
=> (nil imaginary 1 real 0)
procedure( trComplexAddition( cmplx1 cmplx2 )
trMakeComplex(
?real cmplx1->real + cmplx2->real
?imaginary cmplx1->imaginary + cmplx2->imaginary
)
) ; procedure
procedure( trComplexMultiplication( cmplx1 cmplx2 )
trMakeComplex(
?real
cmplx1->real * cmplx2->real -
cmplx1->imaginary * cmplx2->imaginary
?imaginary
cmplx1->imaginary * cmplx2->real +
cmplx1->real * cmplx2->imaginary
)
) ; procedure
trComplexMultiplication( i i ) => (nil imaginary 0 real -1)
In several

vivienluo

result = ncons(nil)相当于创建一个list，该list中包含一个nil的值。
ncons等效于cons( g_element nil )

result->real = real 等于将result的real属性附上real的值
result->imaginary = imaginary等于将result的imaginary属性附上imaginary的值。

所以complex1 = trMakeComplex( ?real 2 ?imaginary 3 )返回的结果为(nil imaginary 3 real 2)